Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 148: 65

Answer

$\{4\}$

Work Step by Step

Step 1. Given the equation $3-\sqrt {x}=\sqrt {2\sqrt x-3}$ Step 2. Take square on both sides to get: $9-6\sqrt {x}+x=2\sqrt x-3$ or $x+12=8\sqrt x$ Step 3. Take square on both sides again to get: $x^2+24x+144=64x$ or $x^2-40x+144=0$ which gives $x=4,36$ Step 4. Check answers in the original equation: only $\{4\}$ fits.
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