Answer
$\{-\frac{7}{4},\frac{1}{2} \}$
Work Step by Step
Step 1. Let $u=(x)^{-1}$, we have $7u^2-10u-8=0$
Step 2. Factor and solve: $(u-2)(7u+4)=0$ thus $u=-\frac{4}{7}, 2$
Step 3. For $u=-\frac{4}{7}$, we have $(x)^{-1}=-\frac{4}{7}$ thus $x=-\frac{7}{4}$
Step 4. For $u=2$, we have $(x)^{-1}=2$ thus $x=\frac{1}{2}$
Step 5. Solution set $\{-\frac{7}{4},\frac{1}{2} \}$