Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 148: 63

Answer

$\{-\frac{2}{9},2\}$

Work Step by Step

Step 1. Given the equation $\sqrt {2\sqrt {7x+2}}=\sqrt {3x+2}$ Step 2. Take square on both sides to get: $2\sqrt {7x+2}=3x+2$ Step 3. Take square on both sides again to get: $28x+8=9x^2+12x+4$ or $9x^2-16x-4=0$ which gives $x=-\frac{2}{9},2$ Step 4. Check answers in the original equation: both $\{-\frac{2}{9},2\}$ fit.
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