Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 148: 62

Answer

$\{27\}$

Work Step by Step

Step 1. Given the equation as $\sqrt {2x-5}=2+\sqrt {x-2}$ Step 2. Take square on both sides to get: $2x-5=4+4\sqrt {x-2}+x-2$ or $x-7=4\sqrt {x-2}$ Step 3. Take square on both sides again to get: $x^2-14x+49=16x-32$ or $x^2-30x+81=0$ which gives $x=3,27$ Step 4. Check answer in the original equation: only $\{27\}$ fits.
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