Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises - Page 121: 34


$\color{blue}{\left\{4-i\sqrt5, 4+i\sqrt5\right\}}$.

Work Step by Step

RECALL: If $x^2=a$, then taking the square root of both sides gives $x = \pm \sqrt{a}$. Take the square root of both sides of the given equation to obtain: $\sqrt{(x-4)^2}=\pm \sqrt{-5} \\x-4 =\pm \sqrt{-1(5)}$ Since $\sqrt{-1}=i$, then the expression above is equivalent to: $x-4=\pm i\sqrt{5}$ Add $4$ to both sides: $x =4 \pm i\sqrt{5}$ Thus, the solution set is $\color{blue}{\left\{4-i\sqrt5, 4+i\sqrt5\right\}}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.