Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises - Page 121: 15


The solutions are $x=1$ and $x=-\dfrac{2}{5}$

Work Step by Step

$5x^{2}-3x-2=0$ Factor the left side of the equation: $(5x+2)(x-1)=0$ Using the zero-factor property, set both factors equal to $0$ and solve each individual equation for $x$: $5x+2=0$ $5x=-2$ $x=-\dfrac{2}{5}$ $x-1=0$ $x=1$ The solutions are $x=1$ and $x=-\dfrac{2}{5}$
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