Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises - Page 121: 18


The solutions are $x=2$ and $x=-\dfrac{5}{6}$

Work Step by Step

$-6x^{2}+7x=-10$ Take all terms to the right side of the equation: $0=6x^{2}-7x-10$ Rearrange: $6x^{2}-7x-10=0$ Factor the left side of the equation: $(6x+5)(x-2)=0$ Using the zero-factor property, set both factors equal to $0$ and solve each individual equation for $x$: $6x+5=0$ $6x=-5$ $x=-\dfrac{5}{6}$ $x-2=0$ $x=2$ The solutions are $x=2$ and $x=-\dfrac{5}{6}$
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