Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises - Page 121: 16


The solutions are $x=3$ and $x=-\dfrac{5}{2}$

Work Step by Step

$2x^{2}-x-15=0$ Factor the left side of the equation: $(2x+5)(x-3)=0$ Using the zero-factor property, set both factors equal to $0$ and solve each individual equation for $x$: $2x+5=0$ $2x=-5$ $x=-\dfrac{5}{2}$ $x-3=0$ $x=3$ The solutions are $x=3$ and $x=-\dfrac{5}{2}$
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