## Precalculus (6th Edition) Blitzer

$(-\infty,1]$
"$y$ is at most $0$" $\qquad$ is written as $\quad y\leq 0.$ Substituing the expression for y, $2x-11+3(x+2)\leq 0 \qquad$ ... simplify $2x-11+3x+6\leq 0$ $5x-5\leq 0\qquad$ ... add $5$ $5x\leq 5\qquad$ ... divide with 5 $x\leq 1$ Solution set = $(-\infty,1]$.