Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 138: 94

Answer

$(-\infty,1]$

Work Step by Step

"$ y $ is at most $0$" $\qquad $ is written as $\quad y\leq 0.$ Substituing the expression for y, $2x-11+3(x+2)\leq 0 \qquad $ ... simplify $2x-11+3x+6\leq 0$ $ 5x-5\leq 0\qquad $ ... add $5$ $ 5x\leq 5\qquad $ ... divide with 5 $ x\leq 1$ Solution set = $(-\infty,1]$.
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