Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 138: 80

Answer

$[-16,2]$

Work Step by Step

$-3|x+7|\geq-27\qquad $ ... divide with $(-3)$ ... $\times $(negative) $\Rightarrow $ change direction $|x+7|\leq 9$ ... $|u| \leq c $ is equivalent to $-c \leq u \leq c.$ $-9\leq x+7\leq 9 \qquad $ ... add $-7$ ... $-16\leq x\leq 2$ Borders are included, The solution set is $[-16,2].$
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