Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 138: 29

Answer

The solution set is $[\displaystyle \frac{20}{3}, \infty)$
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Work Step by Step

The idea is to isolate x on one side. Adding, subtracting or multiplying/dividing with a positive number preserves order (the inequality symbol remains). Multiplying/dividing with a negative number inverts the order (the inequality symbol changes) --- $ 3x-7 \geq 13\qquad $ ... $/+7$ $ 3x \geq 20 \qquad $ ... $/\div 3$, (positive) $ x \displaystyle \geq \frac{20}{3}$ The solution set is $[\displaystyle \frac{20}{3}, \infty)$
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