Work Step by Step
Rewrite as $|11-x| \lt 2$ ... also, $|a-b|=|b-a|$ $|x-11| \lt 2$ ... $|u| \lt c $ is equivalent to $-c \lt u \lt c.$ $-2 \lt x-11 \lt 2 \qquad $ ... add $11$ $9 \lt x \lt 13$ Solution set = $(9,13)$
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