Answer
$(9,13)$
Work Step by Step
Rewrite as
$|11-x| \lt 2$
... also, $|a-b|=|b-a|$
$|x-11| \lt 2$
... $|u| \lt c $ is equivalent to $-c \lt u \lt c.$
$-2 \lt x-11 \lt 2 \qquad $ ... add $11$
$9 \lt x \lt 13$
Solution set = $(9,13)$
