## Precalculus (6th Edition) Blitzer

The statement $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ is true at $x=6$.
Consider the equation, $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ Now, substitute the value $x=6$ in the equation $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ Therefore, \begin{align} & 2\left( 6-3 \right)-17=13-3\left( 6+2 \right) \\ & 2\left( 3 \right)-17=13-3\left( 8 \right) \\ & 6-17=13-18 \\ & -11=-11 \end{align} Hence, the statement $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ is true at $x=6$.