Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 121


The statement $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ is true at $x=6$.

Work Step by Step

Consider the equation, $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ Now, substitute the value $x=6$ in the equation $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ Therefore, $\begin{align} & 2\left( 6-3 \right)-17=13-3\left( 6+2 \right) \\ & 2\left( 3 \right)-17=13-3\left( 8 \right) \\ & 6-17=13-18 \\ & -11=-11 \end{align}$ Hence, the statement $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ is true at $x=6$.
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