## Precalculus (6th Edition) Blitzer

Let us consider the expression $\frac{3x-3}{4x\left( x-1 \right)}$. Now, evaluate the value of the denominator of the given expression for $x=1$. \begin{align} & 4x\left( x-1 \right)=4\times 1\left( 1-1 \right) \\ & =4\times \left( 0 \right) \\ & =0 \end{align} Here the denominator of the fraction is equal to zero. Hence, the expression is not defined for $x=1$. Thus, the given statement does not make sense.