Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 112

Answer

The given statement makes sense.

Work Step by Step

We have to subtract $\frac{3x-5}{x-1}$ from $\frac{x-3}{x-1}$ And write the above statement in the form of a mathematical expression. $\frac{x-3}{x-1}-\frac{3x-5}{x-1}$ Now, perform the subtraction of the rational algebraic expressions. $\begin{align} & \frac{x-3}{x-1}-\frac{3x-5}{x-1}=\frac{x-3-\left( 3x-5 \right)}{x-1} \\ & =\frac{x-3-3x+5}{x-1} \\ & =\frac{-2x+2}{x-1} \end{align}$ And factorize the numerator by taking out a common factor and simplify. $\begin{align} & \frac{x-3}{x-1}-\frac{3x-5}{x-1}=\frac{-2\left( x-1 \right)}{\left( x-1 \right)} \\ & =-2 \end{align}$ Thus, the result of the given algebraic expression is a constant. Hence, the given statement makes sense.
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