Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 111


Does not make sense.

Work Step by Step

When dividing a rational expression, we need to invert the divisor and then multiply it to the first expression $\frac{7x}{x+3}\div\frac{(x+3)^2}{x-5}=\frac{7x}{x+3}\times\frac{x-5}{(x+3)^2}=\frac{7x(x-5)}{(x+3)^3}$. Thus, the statement does not make sense.
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