## Precalculus (6th Edition) Blitzer

$5x^{3}y^{2}$
$(125x^{9}y^{6})^{1/3}==\qquad$... apply $(ab)^{n}=a^{n}b^{n}$ $=125^{1/3}(x^{9})^{1/3}(y^{6})^{1/3}=$ ... recognize a power of 5. $=(5^{3})^{1/3}(x^{9})^{1/3}(y^{6})^{1/3}=$ ... $a^{1/3}$ is the cube root of a. For odd roots, we don't need absolute values. ... apply $(a^{m})^{n}=a^{mn}$ $=5x^{3}y^{2}$