Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 46: 112


$\displaystyle \frac{2x^{3}}{y}$

Work Step by Step

$(8x^{-6}y^{3})^{1/3}(x^{5/6}y^{-1/3})^{6}=\qquad$... apply $(ab)^{n}=a^{n}b^{n}$ .... recognize $8=2^{3}$ $=(2^{3})^{1/3}x^{-6(1/3)}y^{3(1/3)}x^{(5/6)(6)}y^{(-1/3)(6)}$ $=2x^{-2}y^{1}x^{5}y^{-2}\qquad$... apply $a^{m}a^{n}=a^{m+n}$ $=2x^{-2+5}y^{1+(-2)}$ $=2x^{3}y^{-1}\qquad$... apply $a^{-n}=\displaystyle \frac{1}{a^{n}}$ $=\displaystyle \frac{2x^{3}}{y}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.