## Precalculus (6th Edition) Blitzer

$\sqrt[3]{x^2}$
RECALL: $\sqrt[n]{a^m} = a^{\frac{m}{n}}.$ Use the rule above to obtain $x^{\frac{6}{9}} \\=x^{\frac{2}{3}}.$ Write the expression in radical form using the rule above to obtain $\sqrt[3]{x^2}.$