Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 46: 77



Work Step by Step

Simplify each radicand to obtain $5\sqrt[3]{8(2)}+\sqrt[3]{27(2)} \\=5\sqrt[3]{2^3(2)}+\sqrt[3]{3^3(2)} \\=5\cdot2\sqrt[3]{2} + 3\sqrt [3]{2} \\=10\sqrt[3]{2} + 3\sqrt[3]{2}.$ RECALL: The distributive property states that for any real numbers a, b, and c, $ac + bc = (a+b)c.$ Use the distributive to obtain $(10+3)\sqrt[3]{2} \\=13\sqrt[3]{2}.$
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