$ x=6t+3$ ; $ y=13t-1$
Work Step by Step
For a line, we have: $(3,-1); (9,12)$ $ x_1=3, x_2=9,y_1=-1, y_2=12$ Now, in parametric from: $ x=(x_2-x_1) t+x_1=6t+3$ and $ y=(y_2-y_1)t_1+y_1 =13t-1$ So, $ x=6t+3$ ; $ y=13t-1$
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