Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1020: 48

Answer

$ x=4+3 \cos t $ ; $ y=-1+5 \sin t $

Work Step by Step

Standard form of a Ellipse: $\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$ $ h=4, k=-1; a=3; b=5$ Now, in parametric from: $ x=h+a \cos t =4+3 \cos t $ and $ y=k+b \sin t =-1+5 \sin t $ So, $ x=4+3 \cos t $ ; $ y=-1+5 \sin t $
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