Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1020: 45

Answer

$ x=3+6 \cos t $ ; $ y=5+6 \sin t $

Work Step by Step

The standard form of a circle is: $(x-h)^2+(y-k)^2=r^2$ $ h=3, k=5; r=6$ Now, in parametric from: $ x=h+r \cos t =3+6 \cos t $ and $ y=y+k \sin t =5+6 \sin t $ So, $ x=3+6 \cos t $ ; $ y=5+6 \sin t $
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