Answer
$ x=3+6 \cos t $ ; $ y=5+6 \sin t $
Work Step by Step
The standard form of a circle is:
$(x-h)^2+(y-k)^2=r^2$
$ h=3, k=5; r=6$
Now, in parametric from:
$ x=h+r \cos t =3+6 \cos t $
and $ y=y+k \sin t =5+6 \sin t $
So, $ x=3+6 \cos t $ ; $ y=5+6 \sin t $
