focus $(0,3)$, directrix $y=-3$ See graph.
Work Step by Step
Step 1. Given $x^2=12y$, we have $4p=12$ and $p=3$ with the parabola opening upwards and vertex at $(0,0)$. Step 2. We can find the focus at $(0,3)$ and directrix as $y=-3$ Step 3. We can graph the parabola as shown in the figure.