Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 996: 14

Answer

focus $(0,\frac{3}{2})$, directrix $y=-\frac{3}{2}$ see graph.
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Work Step by Step

Step 1. Rewriting the equation as $x^2=6y$, we have $4p=6$ and $p=\frac{3}{2}$ with the parabola opening upwards and vertex at $(0,0)$. Step 2. We can find the focus at $(0,\frac{3}{2})$ and directrix as $y=-\frac{3}{2}$ Step 3. We can graph the parabola as shown in the figure.
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