Answer
focus $(-\frac{1}{8},0)$, directrix $x=\frac{1}{8}$
see graph.
Work Step by Step
Step 1. Rewriting the equation as $y^2=-\frac{1}{2}x$, we have $4p=-\frac{1}{2}$ and $p=-\frac{1}{8}$ with the parabola opening to the left and vertex at $(0,0)$.
Step 2. We can find the focus at $(-\frac{1}{8},0)$ and directrix as $x=\frac{1}{8}$
Step 3. We can graph the parabola as shown in the figure.