focus $(-2,0)$, directrix $x=2$
Work Step by Step
Step 1. Given $y^2=-8x$, we have $4p=-8$ and $p=-2$ with the parabola opening to the left and vertex at $(0,0)$. Step 2. We can find the focus at $(-2,0)$ and directrix as $x=2$ Step 3. We can graph the parabola as shown in the figure.