Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.5 - Determinants and Cramer's Rule - Exercise Set - Page 947: 83


The standard form is, ${{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}={{3}^{2}}$.

Work Step by Step

The standard form of the circle is, ${{\left( x-{x}' \right)}^{2}}+{{\left( y-{y}' \right)}^{2}}={{r}^{2}}$ To make the equation in standard form, we will proceed by completing the square method as follows: $\begin{align} & {{x}^{2}}+{{y}^{2}}-2x+4y=4 \\ & \left( {{x}^{2}}-2\cdot x\cdot 1+{{1}^{2}} \right)+\left( {{y}^{2}}+2\cdot y\cdot 2+{{2}^{2}} \right)-5=4 \\ & {{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}-5=4 \\ & {{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}=9 \end{align}$ Hence, the required standard form of the circle is, ${{\left( x-1 \right)}^{2}}+{{\left( y+2 \right)}^{2}}={{3}^{2}}$.
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