#### Answer

The dimensions of the rectangles are 25 feet by 11 feet.

#### Work Step by Step

Consider the length and breadth of the rectangle to be $l$ and $b$ respectively.
It is provided that the perimeter of the rectangle is $72$ feet. Consider the perimeter to be denoted by $p$, so:
$p=2\left( l+b \right)$
Substitute the value of $p$ in the above equation:
$\begin{align}
& 72=2\left( l+b \right) \\
& l+b=36
\end{align}$
Also, it is provided that the length of the rectangle is 14 feet more than the width:
$l=b+14$
So,
$\begin{align}
& l+b=36 \\
& b+14+b=36 \\
& 2b=36-14 \\
& b=11
\end{align}$
So, the length will be:
$\begin{align}
& l=b+14 \\
& =11+14 \\
& =25
\end{align}$
The dimensions of the rectangles are 25 feet by 11 feet.