Answer
a) The $x$ -intercept is $\pm 3$.
b) The $y$ -intercept is $\pm 2$.
Work Step by Step
(a)
To calculate the x-intercept, put $y=0$:
$\begin{align}
& \frac{{{x}^{2}}}{9}+0=1 \\
& {{x}^{2}}=9 \\
& x=\pm 3
\end{align}$
The $x$ -intercept is $\pm 3$.
(b)
To calculate the y-intercept, put $x=0$
$\begin{align}
& 0+\frac{{{y}^{2}}}{4}=1 \\
& {{y}^{2}}=4 \\
& y=\pm \sqrt{4} \\
& =\pm 2
\end{align}$
The $y$ -intercept is $\pm 2$.
