Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.5 - Determinants and Cramer's Rule - Exercise Set - Page 946: 55

Answer

The value of the second order determinant is $ad-bc$.

Work Step by Step

To evaluate a second-order determinant, we will find the difference of the product of the two diagonals. Example: $\text{For any determinant,}$ $\left| \begin{matrix} a & b \\ c & d \\ \end{matrix} \right|=ad-bc$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.