## Precalculus (6th Edition) Blitzer

The value of $x$ is $=26$
Consider, $\left| \begin{matrix} x+3 & -6 \\ x-2 & -4 \\ \end{matrix} \right|=28$ Calculate the above determinant as follows: $\left| \begin{matrix} x+3 & -6 \\ x-2 & -4 \\ \end{matrix} \right|=28$ This implies that, $-4\left( x+3 \right)+6\left( x-2 \right)=28$ Simplify the above equation, $-4x-12+6x-12=28$ Or, $2x=52$ Divide by $2$. Now, $x=26$. Hence, $x=26$