Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.5 - Determinants and Cramer's Rule - Exercise Set - Page 946: 45

Answer

The value of $x$ is $-11$.

Work Step by Step

Consider, $\left| \begin{matrix} -2 & x \\ 4 & 6 \\ \end{matrix} \right|=32$ Calculate the above determinant as given: $\left| \begin{matrix} -2 & x \\ 4 & 6 \\ \end{matrix} \right|=32$ This implies that, $\left( -2\times 6 \right)-\left( 4\times x \right)=32$ Simplify the above equation, $-12-4x=32$ Add 12 to both sides to get, $-4x=44$ Divide by $-4$. Then, $x=-11$. Hence, $x=-11$.
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