Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.5 - Systems of Inequalities - Exercise Set - Page 865: 117

Answer

$x\lt1$
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Work Step by Step

Step 1. Rewrite the inequality as $\frac{x-2}{x-1}-1=\frac{x-2-x+1}{x-1}=\frac{-1}{x-1}\geq0$ or $\frac{1}{x-1}\leq0$ Step 2. We can find the solution set of the above as $x\lt1$ Step 3. We can graph the solution set on a real number line as shown in the figure.
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