## Precalculus (6th Edition) Blitzer

The statement does not make sense as $\left( 0,0 \right)$ cannot be used if it lies on the given equation.
If graphing a linear inequality, always use a test point that does not lie on the given inequality to check which region should be shaded. When a test point $\left( 0,0 \right)$ lies on the given inequality, it cannot be used as a test point. The test point can be any coordinate in the graph. When that point satisfies the inequality, the region towards the test point must be shaded, and if not, the region opposite to the point is shaded. Thus, the given statement does not make sense. And the correct statement should be: the test point can be any coordinate in the graph that does not lie on the provided inequality.