#### Answer

$(\dfrac{1}{5},\dfrac{18}{5})$ or, $(1,2)$

#### Work Step by Step

Here, we have $y=4-2x$
Now, $(x+1)^2+[(4-2x)^2-2]^2=4$
This gives: $5x^2-6x+1=0$
This yields : $(5x-1) (x-1)=0$
when $x=\dfrac{1}{5}$ then we have $y=4-2(\dfrac{1}{5})=\dfrac{18}{5}$
when $x=1$ then we have $y=4-2(1)=2$
Hence, our answers are: $(\dfrac{1}{5},\dfrac{18}{5})$ or, $(1,2)$