#### Answer

$(-1,2)$ or, $(4,-3)$

#### Work Step by Step

Here, we have $y=1-x$
Now, $x^2+x(1-x)-(1-x)^2=-5$
This gives: $-x^2+3x+4=0 $ or, $x^2-3x-4=0 $
This yields : $(x+1) (x-4)=0$
when $x=-1$ then we have $y=1-(-1)=2$
when $x=4$ then we have $y=1-4=-3$
Hence, our answers are: $(-1,2)$ or, $(4,-3)$