Answer
$(0,1)$ or, $(4,-3)$
Work Step by Step
Here, we have $y=1-x$
Now, $(x-1)^2+[(1-x)^2+2)^2=10$
This gives: $2x^2-8x=0$
This yields : $x(x-4)=0$
when $x=0$ then we have $y=1-0=1$
when $x=4$ then we have $y=1-4=-3$
Hence, our answers are: $(0,1)$ or, $(4,-3)$