## Precalculus (6th Edition) Blitzer

$\left( 6,\frac{5\pi }{3} \right)$
It is given that the horse is in the inner circle; therefore, $r=6$ As the horse is $\frac{5}{6}$ of the way around the merry-go-round, therefore, the angle intercepted by the horse will be given by, $2\pi \times \frac{5}{6}=\frac{5\pi }{3}$ Therefore, the polar coordinate is $\left( 6,\frac{5\pi }{3} \right)$.