Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.3 - Polar Coordinates - Exercise Set - Page 743: 53

Answer

The polar equation of ${{x}^{2}}+{{y}^{2}}=9$ which express $r$ in terms of $\theta $ is $r=3$.

Work Step by Step

The relation between polar coordinates and rectangular coordinates can be represented as below: $x=r\cos \theta \ \text{ and }\ y=r\sin \theta $ …… (2) Substitute the values of $x\ \text{ and }\ y$ from (2) in (1) to get, $\begin{align} & {{x}^{2}}+{{y}^{2}}=9 \\ & {{\left( r\cos \theta \right)}^{2}}+{{\left( r\sin \theta \right)}^{2}}=9 \\ & {{r}^{2}}\left( {{\cos }^{2}}\theta +{{\sin }^{2}}\theta \right)=9 \end{align}$ As, $\left( {{\cos }^{2}}\theta +{{\sin }^{2}}\theta \right)=1$ From here we get, $\begin{align} & {{r}^{2}}=9 \\ & r=3 \end{align}$
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