Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.3 - Polar Coordinates - Exercise Set - Page 743: 62


The rectangular equation is, $y=\sqrt{3}x$

Work Step by Step

Using, $\tan \theta =\frac{y}{x}$, we will convert the given polar equation to the rectangular equation. Therefore, $\begin{align} & \tan \frac{\pi }{3}=\frac{y}{x} \\ & y=\tan \frac{\pi }{3}x \\ & y=\sqrt{3}x \end{align}$ And the graph is shown above.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.