Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.3 - Polar Coordinates - Exercise Set - Page 743: 83


$\left( 15,\frac{4\pi }{3} \right)$

Work Step by Step

Since it is given that the horse is in the outer circle, therefore r will be calculated as below: $\begin{align} & r=6+3+3+3 \\ & =15 \end{align}$ The horse is $\frac{2}{3}$ of the way around the merry-go-round, therefore, the angle intercepted by the horse is given by: $2\pi \times \frac{2}{3}=\frac{4\pi }{3}$
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