Answer
$\dfrac{1}{2 \sqrt 3}$ or, $\dfrac{\sqrt 3}{6}$
Work Step by Step
Solve. $\tan ( \dfrac{\pi}{6}) \times \cos ( \dfrac{\pi}{3})- \cos \dfrac{\pi}{2} $
$=\dfrac{1}{\sqrt 3} \times \dfrac{1}{2} -0$
$= \dfrac{1}{2 \sqrt 3} \times \dfrac{\sqrt 3}{ \sqrt 3}$
$= \dfrac{\sqrt 3}{6}$
