Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Test - Page 647: 2


$26.18$ feet

Work Step by Step

We have $\theta =75^{\circ}$ The length of the arc is given by (first convert $\theta$ into radians): $s=r\theta$ $s=\dfrac{75}{360^{\circ}} \times 2 \pi \times 20= \dfrac{25 \pi}{3}$ $s=\dfrac{25 \pi}{3}=\dfrac{25 \times 3.142}{3}=26.18$ ft
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