Precalculus (6th Edition) Blitzer

$26.18$ feet
We have $\theta =75^{\circ}$ The length of the arc is given by (first convert $\theta$ into radians): $s=r\theta$ $s=\dfrac{75}{360^{\circ}} \times 2 \pi \times 20= \dfrac{25 \pi}{3}$ $s=\dfrac{25 \pi}{3}=\dfrac{25 \times 3.142}{3}=26.18$ ft