Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Test - Page 647: 23


$ N 80^{\circ} W $

Work Step by Step

Since, $\theta =10^{\circ}$ So, the bearing measurement is: $180^{\circ}-90^{\circ}-10^{\circ}=80^{\circ}$ So, our required answer is: $ N 80^{\circ} W $
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