## Precalculus (6th Edition) Blitzer

a) $b-a$ b) $\dfrac{a-1}{b}$
a) $\sin (- \theta) +\cos (-\theta) =-\sin \theta+\cos \theta$ or, $=-a+b$ or, $=b-a$ b) $\tan (\theta) -\sec (\theta) =\dfrac{\sin \theta}{\cos \theta}-\dfrac{1}{\cos \theta}$ or, $=\dfrac{\sin \theta-1}{\cos \theta}$ or, $=\dfrac{a-1}{b}$