Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 610: 43


Please see below.

Work Step by Step

Please note that since $\sec (Bx-C)=\frac{1}{\cos (Bx-C)}$, the period of the secant function is the same as the period of the cosine function, that is, $\frac{2\pi }{B}$. So the period of the function $y=2 \sec (x+ \pi )$ is $\frac{2\pi }{1 }=2\pi$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.