Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 610: 28

Answer

See graph and explanations.
1583870539

Work Step by Step

Step 1. As $sec(\frac{\pi}{2} x)=\frac{1}{cos(\frac{\pi}{2} x)}$, we can use the original function $y=-3cos(\frac{\pi}{2} x)$to obtain the reciprocal function $y=-3sec(\frac{\pi}{2} x)$. Step 2. The original function has zeros at $x=\pm1,\pm3, ...$ which become vertical asymptotes of the new function. Step 3. Using the reciprocal property, we can obtain the new function $y=-3sec(\frac{\pi}{2} x)$, shown as the red curves in the figure.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.