## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 610: 32

#### Answer

Please see below.

#### Work Step by Step

Please note that since $\csc (Bx-C)=\frac{1}{\sin (Bx-C)}$, the period of the cosecant function is the same as the period of the sine function, that is, $\frac{2\pi }{B}$. So the period of the function $y=\frac{3}{2}\csc \frac{x}{4}$ is $\frac{2\pi }{\frac{1}{4}}=8\pi$.

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