Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 610: 25

Answer

See graph and explanations.

Work Step by Step

Step 1. As $csc(\frac{x}{2})=\frac{1}{sin(\frac{x}{2})}$, we can use the original function $y=-\frac{1}{2}sin(\frac{x}{2})$to obtain the reciprocal function $y=-\frac{1}{2}csc(\frac{x}{2})$. Step 2. The original function has zeros at $x=0,\pm 2\pi,\pm 4\pi, ...$ which become vertical asymptotes of the new function. Step 3. Using the reciprocal property, we can obtain the new function $y=-\frac{1}{2}csc(\frac{x}{2})$, shown as the red curve in the figure.
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